Re my earlier post, here is a worked example showing that you can use the quadratic formula approach to work out what non-decimal base a calculation is in.
(Update: Rational Anarchist developed this technique independently and posted a worked example a few minutes ago in the comments to the earlier post. So this is a Newton v Leibniz type spat...)
Problem
"15 x 36 = 642. This doesn't work in decimal/base ten. What base is it in?"
Solution
You express the first part as: (x + 5) x (3x + 6)
You multiply those to get: 3x^2 + 21x + 30 (expression A).
You express the second part as: 6x^2 + 4x + 2 (expression B)
You subtract expression A from expression B and get:
3x^2 - 17x - 28 = 0
You solve this using your preferred method.
Using factorisation, you get (3x + 4) x (x - 7) = 0
So x (the base) could be -4/3 or 7. The base must be at least 7 because the highest digit in the original calculation was "6", so rule out -4/3 and try with 7.
Check
You have to convert the given equation from base 7 to base 10 and see if it works.
Base 7................Base 10
15.......................7 + 5 = 12
36......................(3 x 7) + 6 = 27
642....................(6 x 49) + (4 x 7) + 2 = 324
15 x 36 = 642...12 x 27 = 324
Sorted!
NB - If the calculation you are given is a division - i.e. "642 ÷ 15 = 36", then you just turn it into the multiplication 15 x 36 = 642" and use the same approach,
Friday, 10 January 2020
Fun With Numbers - worked example
My latest blogpost: Fun With Numbers - worked exampleTweet this! Posted by Mark Wadsworth at 19:23
Labels: Maths
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